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Forum: Electrical & Computer Engineering :: Electric Circuits :: Thevenin and Norton  New Topic
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aac13 #3 Sat 4 Apr 2009 4:07:00 PM
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Joined Wed 21 Jan 2009
Posts 151
Find the Thévenin equivalent with respect to the terminals a, b in the circuit shown.


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aac13 Sat 4 Apr 2009 4:08:00 PM
Student
Joined Wed 21 Jan 2009
Posts 151

IT = (vT – v1)/20  +  (vT – 40i)/60

(v1 – 40v)/16  +  v1/80  +  (v1 – vT)/20  =  0


10v1 - 200i = 4vT                 i = -v1/80,          200 i = -2.5v1

12.5v1 = 4vT;                v1 = 0.32vT

i = - v1/80  =  -0.32vT /80

40i = - 0.16vT

iT =  (vT – 0.32vT)/20  +  (vT + 0.16vT)/60

    =  ( (0.68 vT)(3) + 1.16vT ) /60

    =  ( (2.04 + 1.16)vT )/60  =  3.20vT/60

VT /iT  =  60/3.2  =  18.75 Ω

è RTh = 18.75 Ω


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