__Answer 12.__

The input resistance is Vi/i_{i}= 35 K

To get the out resistance, turn of the source and plug in a test source, we get that Vt/i_{t}= 24 K

Vz/Vi= 20 x (60/80)

Vo/V_{2}= G x 24/44 x 20

Vo/V_{2} x Vz/Vi= 20 x (60/80) x 2 x 24/44 x 20= 327.27 V/V

I_{0}/i_{i}= (V_{0}/R_{0}) / (V_{i}/ R_{i}) = V_{0}/V_{i} x R_{i}/R_{0}= 327.27 x 35/20= 572.7